Koofer Test 1 Key

 1  6	
 2  6	
 3  1   The executable is produced by the linker; 
        design logic is your responsibility.
 4  1
 5  2   There is no ** arithmetic operator in C++.
 6  1
 7  1
 8  2   Single quotes are used to delimit a single
        character; this is a string of three characters,
        properly written as "abc".
 9  2   Missing curly braces.  The if-clause is just the
        single statement fred = zach; and so there is no
        uncompleted if to match the else.
10  1
11  2   The extract operator >> can only be used with an 
        input stream; cout is an output stream.
12  3   12 / 3.0 + 5 / 2 == 4.0 + 2 == 6.0
13  6   10 % 1 + 3 / 5 == 0 + 0 = 0
14  2   10 / 3 * 9 == 3 * 9 == 27
15  1   9.0 - 6.0 / 2.0 + 3.0 == 9.0 - 3.0 + 3.0 == 9.0
16  4   5.0 / 3.0 == 1.666666..; assigning that to an
        int variable truncates it to 1
17  2   5 / 2.0 == 2.5
18  5   a char variable can hold only one character, 
        not a character string
19  4   This is not a particularly good question.  The
        expression (34 <= 50) is true, so the int variable
        anInt will be assigned a value representing true.
        That value may or may not be 1.
20  3   15 / 6 == 2; assigning that to a float variable
        promotes it to 2.0

For 21 and 22, the input statement will act as follows:

         cin >> i1     // reads the first integer value, 14
             >> i2     // reads the next integer value, 7
             >> i3;    // fails since the next value in the
                       // input stream is a period, which
                       // cannot be part of an integer value
21  3   
22  4   Again, not a very good question since the actual
        value of i3 after a failed read attempt targeting
        i3 depends on the implementation of your compiler.
        With Visual C++, i3 will be unchanged.  With other
        compilers, the value of i3 may be random or 0.

For 23 and 24, the input statement will act as follows:

         cin >> i1     // reads the first integer value, 14
             >> i2     // reads the next decimal value, 7.9
             >> c1     // reads the next nonwhitespace character, '1'
             >> c2;    // reads the next nonwhitespace character, 'A'
23  2
24  3

For 25 and 26, the input statement will act as follows:

         cin >> i1     // reads the first integer value, 14
             >> i2     // reads the next integer value, 7
             >> c1     // reads the next nonwhitespace character, '.'
             >> i3;    // reads the next integer value, 9
25  2
26  2

27  2   The expression 30 + 12 is evaluated and its value is printed;
        the setw() setting doesn't allow for any space between the
        end of the string "The answer is" and the following value.
28  3
29  ?   Bad question -- should have setw() and setprecision()
        for formatting.  The closest answer would be 2.
30  1   
31  1
32  2
33  ?   Not a syntax error.  The expression is evaluated from left
        to right.  C <= B is true; the value of true is then compared
        to A.  If true is represented by 1, the value of the second
        comparison is then also true.
34  1
35  1
36  1   Remember:  && evaluates before || in the absence of parens.
37  2   The ignore() reads and discards the first four characters.
38  2   The ignore() reads and discards the first line.
39  3
40  4
41  3
42  2   Hard question:  consider the case J >= K.
43  5   One line for each endl printed.
44  8   1a1a1a1a1a starts with a digit; if is a reserved word
45  3   
46  3
47  4,5 Badly chosen answers.  A syntax error would prevent
        compilation (that includes undeclared identifiers).
        Answer 2 is not a useful option.  Missing curly braces
        might cause a compile-time error; missing curly braces
        could also simple cause the code to operate incorrectly,
        perhaps producing a run-time error, perhaps producing
        incorrect results.
48  3   The else goes with the first if, because of the curly
        braces.
49  3
50  3