Koofer Test 2 Key

For questions 1 and 2, the while loop body is executed three times:
       count:  3  6 12 24
       pass:   2  3  4  5
 1  c	
 2  c	

 3  c   As opposed to a do-while (evaluated at end).
 4  f	while and for; switch and if...else are selection mechanisms
 5  e   &'s in the prototype and definition header
 6  b	Execute "case 0" clause, changing anInt to 0.
 7  d	Execute "case 1" clause, but no break, so falls through to
	the break in "case 3" and sets anInt to 11.
 8  a   anInt == 11, so executes default clause

For questions 0 and 10:  First is passed by reference, Second by value.
   The first assignment in Remainder() changes the value of First to
   117%11, which is 7.
   The second assignment in Remainder does not change Second.
 9  c   
10  a

11  a   Nothing in this program changes the value Temp is initialized to.
	Remember the scope rules.
12  b   First and Second are passed by value, so neither is changed.

For questions 13-15:  notice that x is an int, so the assignment makes
    x == 2, not 2.6.  Also notice that there is no local variable Temp
    in QuadFunc(), so the assigment there modifies the global float variable
    Temp.  Now just do the arithmetic, and Temp == 9.5.  Finally, the return
    value for QuadFunc() is int, so the value 9 is returned and printed.
13  b	
14  c	
15  f	

16  a   
17  b   (at least not unless you pass them as parameters)
18  b   Can't assign an array to an array (use for loop instead).
19  b   Can't add arrays (or do assignment for that matter).
20  a   Adds fourth element of first[] and fourth element of second[],
	storing the result in the fourth cell of third[]
21  a   Adds second element of first[] and third element of second[],
	storing the result in the first cell of third[]
22  a   
23  b	First parameter to DoSomething() must be an array; first[3]
	is just a simple int variable.
24  a	
25  e	display() prints: {-4, 0, 1}
26  c	
27  d   f3() calculates: 3*-4 + 2*0 + 1*2 == -10
28  g	f2() modifies only its first parameter

For questions 29-32:  the point here is scope.  
29  b   passed to MaxVal() in call after line 6
30  a	
31  c	line 7 refers to the local Big, declared in line 6 and not
	modified by MaxVal()
32  a	MaxVal() doesn't have a local Big, nor is Big passed as a 
	parameter -- therefore MaxVal() must reference the global Big

33  c   We haven't covered this yet; in any case, binary search only

For questions 34-38, we haven't covered sorting yet either.  However,
this is just asking to reproduce code given in the notes.
34  c	
35  a	
36  a	
37  c	
38  d	

39  b	
40  e	The formal parameter is an alias for the actual parameter, but
	the function is forbidden to modify the value of the formal 
	parameter (enforced by the compiler).